3x^2/3-17x^1/3+20=0

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Solution for 3x^2/3-17x^1/3+20=0 equation: 


x in (-oo:+oo)

(3*x^2)/3-((17*x^1)/3)+20 = 0

(3*x^2)/3+(-17/3)*x+20 = 0

x^2-17/3*x+20 = 0

DELTA = (-17/3)^2-(1*4*20)

DELTA = -431/9

DELTA < 0

x belongs to the empty set

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